The interaction between charged objects is a noncontact force that acts over some distance of separation. Charge, charge and distance. Every electrical interaction involves a force that highlights the importance of these three variables. Whether it is a plastic golf tube attracting paper bits, two likecharged balloons repelling or a charged Styrofoam plate interacting with electrons in a piece of aluminum, there is always two charges and a distance between them as the three critical variables that influence the strength of the interaction. In this section of Lesson 3, we will explore the importance of these three variables.
The electrical force, like all forces, is typically expressed using the unit Newton. Being a force, the strength of the electrical interaction is a vector quantity that has both magnitude and direction. The direction of the electrical force is dependent upon whether the charged objects are charged with like charge or opposite charge and upon their spatial orientation. By knowing the type of charge on the two objects, the direction of the force on either one of them can be determined with a little reasoning. In the diagram below, objects A and B have like charge causing them to repel each other. Thus, the force on object A is directed leftward (away from B) and the force on object B is directed rightward (away from A). On the other hand, objects C and D have opposite charge causing them to attract each other. Thus, the force on object C is directed rightward (toward object D) and the force on object D is directed leftward (toward object C). When it comes to the electrical force vector, perhaps the best way to determine the direction of it is to apply the fundamental rules of charge interaction (opposites attract and likes repel) using a little reasoning.
The quantitative expression for the effect of these three variables on electric force is known as Coulomb’s law. Coulomb’s law states that the electrical force between two charged objects is directly proportional to the product of the quantity of charge on the objects and inversely proportional to the square of the separation distance between the two objects. In equation form, Coulomb’s law can be stated as
The Coulomb’s law equation provides an accurate description of the force between two objects whenever the objects act as point charges. A charged conducting sphere interacts with other charged objects as though all of its charge were located at its center. While the charge is uniformly spread across the surface of the sphere, the center of charge can be considered to be the center of the sphere. The sphere acts as a point charge with its excess charge located at its center. Since Coulomb’s law applies to point charges, the distance d in the equation is the distance between the centers of charge for both objects (not the distance between their nearest surfaces).
The symbols Q_{1} and Q_{2} in the Coulomb’s law equation represent the quantities of charge on the two interacting objects. Since an object can be charged positively or negatively, these quantities are often expressed as “+” or “” values. The sign on the charge is simply representative of whether the object has an excess of electrons (a negatively charged object) or a shortage of electrons (a positively charged object). It might be tempting to utilize the “+” and “” signs in the calculations of force. While the practice is not recommended, there is certainly no harm in doing so. When using the “+” and “” signs in the calculation of force, the result will be that a “” value for force is a sign of an attractive force and a “+” value for force signifies a repulsive force. Mathematically, the force value would be found to be positive when Q_{1} and Q_{2} are of like charge – either both “+” or both ““. And the force value would be found to be negative when Q_{1} and Q_{2} are of opposite charge – one is “+” and the other is ““. This is consistent with the concept that oppositely charged objects have an attractive interaction and like charged objects have a repulsive interaction. In the end, if you’re thinking conceptually (and not merely mathematically), you would be very able to determine the nature of the force – attractive or repulsive – without the use of “+” and “” signs in the equation.
In physics courses, Coulomb’s law is often used as a type of algebraic recipe to solve physics word problems. Three such examples are shown here.
The first step of the strategy is the identification and listing of known information in variable form. Here we know the charges of the two objects (Q_{1} and Q_{2}) and the separation distance between them (d). The next step of the strategy involves the listing of the unknown (or desired) information in variable form. In this case, the problem requests information about the force. So F_{elect} is the unknown quantity. The results of the first two steps are shown in the table below.
Given:

Find:

F_{elect} = 9.0 x 10^{9} N
The force of repulsion of two +1.00 Coulomb charges held 1.00 meter apart is 9 billion Newton. This is an incredibly large force that compares in magnitude to the weight of more than 2000 jetliners.
This problem was chosen primarily for its conceptual message. Objects simply do not acquire charges on the order of 1.00 Coulomb. In fact, more likely Q values are on the order of 10^{9} or possibly 10^{6} Coulombs. For this reason, a Greek prefix is often used in front of the Coulomb as a unit of charge. Charge is often expressed in units of microCoulomb (µC) and nanoCoulomb (nC). If a problem states the charge in these units, it is advisable to first convert to Coulombs prior to substitution into the Coulomb’s law equation. The following unit equivalencies will assist in such conversions.
The problemsolving strategy used in Example A included three steps:
This same problemsolving strategy is demonstrated in Example B below.
Given:

Find:

F_{elect} = 9.23 x 10^{7} N
Note that the “” sign was dropped from the Q_{1} and Q_{2} values prior to substitution into the Coulomb’s law equation. As mentioned above, the use of “+” and “” signs in the equation would result in a positive force value if Q_{1} and Q_{2} are like charged and a negative force value if Q_{1} and Q_{2} are oppositely charged. The resulting “+” and “” signs on F signifies whether the force is attractive (a “” F value) or repulsive (a “+” F value).
Given:

Find:

The final step of the strategy involves substituting known values into the Coulomb’s law equation and using proper algebraic steps to solve for the unknown information. In this case, the algebra is done first and the substitution is performed last. This algebra and substitution is shown below.
d^{2} = k • Q_{1} • Q_{2 }/ F_{elect}
d = SQRT(k • Q_{1} • Q_{2}) / F_{elect}
d = SQRT [(9.0 x 10^{9} N•m^{2}/C^{2}) • (8.21 x 10^{6} C) • (+3.37 x 10^{6} C) / (0.0626 N)]
d = Sqrt [ +3.98 m^{2 }]
d = +1.99 m
Electrical force and gravitational force are the two noncontact forces discussed in The Physics Classroom tutorial. Coulomb’s law equation for electrical force bears a strong resemblance to Newton’s equation for universal gravitation.
The inverse square relationship between force and distance that is woven into the equation is common to both noncontact forces. This relationship highlights the importance of separation distance when it comes to the electrical force between charged objects. It is the focus of the next section of Lesson 3.
Sometimes it isn’t enough to just read about it. You have to interact with it! And that’s exactly what you do when you use one of The Physics Classroom’s Interactives. We would like to suggest that you combine the reading of this page with the use of our Coulomb’s Law Interactive. You can find it in the Physics Interactives section of our website. The Coulomb’s Law Interactive allows a learner to explore the effect of charge and separation distance upon the amount of electric force between two charged objects.
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